8(x-4)=-7(x-3)+29

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Solution for 8(x-4)=-7(x-3)+29 equation: 



8(x-4)=-7(x-3)+29

We move all terms to the left:

8(x-4)-(-7(x-3)+29)=0

We multiply parentheses

8x-(-7(x-3)+29)-32=0



We calculate terms in parentheses: -(-7(x-3)+29), so:

-7(x-3)+29

We multiply parentheses

-7x+21+29

We add all the numbers together, and all the variables

-7x+50

Back to the equation:

-(-7x+50)



We get rid of parentheses

8x+7x-50-32=0

We add all the numbers together, and all the variables

15x-82=0

We move all terms containing x to the left, all other terms to the right

15x=82

x=82/15

x=5+7/15

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