8(x-4)=2(4x-6)+x

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Solution for 8(x-4)=2(4x-6)+x equation: 



8(x-4)=2(4x-6)+x

We move all terms to the left:

8(x-4)-(2(4x-6)+x)=0

We multiply parentheses

8x-(2(4x-6)+x)-32=0



We calculate terms in parentheses: -(2(4x-6)+x), so:

2(4x-6)+x

We add all the numbers together, and all the variables

x+2(4x-6)

We multiply parentheses

x+8x-12

We add all the numbers together, and all the variables

9x-12

Back to the equation:

-(9x-12)



We get rid of parentheses

8x-9x+12-32=0

We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20

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