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8(x-4)=2(x+3)-(2x+4)
We move all terms to the left:
8(x-4)-(2(x+3)-(2x+4))=0
We multiply parentheses
8x-(2(x+3)-(2x+4))-32=0
We calculate terms in parentheses: -(2(x+3)-(2x+4)), so:We add all the numbers together, and all the variables
2(x+3)-(2x+4)
We multiply parentheses
2x-(2x+4)+6
We get rid of parentheses
2x-2x-4+6
We add all the numbers together, and all the variables
2
Back to the equation:
-(2)
8x-34=0
We move all terms containing x to the left, all other terms to the right
8x=34
x=34/8
x=4+1/4
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