8(x-4)=2(x-1)

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Solution for 8(x-4)=2(x-1) equation:



8(x-4)=2(x-1)
We move all terms to the left:
8(x-4)-(2(x-1))=0
We multiply parentheses
8x-(2(x-1))-32=0
We calculate terms in parentheses: -(2(x-1)), so:
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
We get rid of parentheses
8x-2x+2-32=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5

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