8(x-4)=3x+6+4x

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Solution for 8(x-4)=3x+6+4x equation: 



8(x-4)=3x+6+4x

We move all terms to the left:

8(x-4)-(3x+6+4x)=0

We add all the numbers together, and all the variables

8(x-4)-(7x+6)=0

We multiply parentheses

8x-(7x+6)-32=0

We get rid of parentheses

8x-7x-6-32=0

We add all the numbers together, and all the variables

x-38=0

We move all terms containing x to the left, all other terms to the right

x=38

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