8(x-4)=6(x-4)-8

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Solution for 8(x-4)=6(x-4)-8 equation: 



8(x-4)=6(x-4)-8

We move all terms to the left:

8(x-4)-(6(x-4)-8)=0

We multiply parentheses

8x-(6(x-4)-8)-32=0



We calculate terms in parentheses: -(6(x-4)-8), so:

6(x-4)-8

We multiply parentheses

6x-24-8

We add all the numbers together, and all the variables

6x-32

Back to the equation:

-(6x-32)



We get rid of parentheses

8x-6x+32-32=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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