8(x-5)+1=4x-2(-2x+1)

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Solution for 8(x-5)+1=4x-2(-2x+1) equation: 



8(x-5)+1=4x-2(-2x+1)

We move all terms to the left:

8(x-5)+1-(4x-2(-2x+1))=0

We multiply parentheses

8x-(4x-2(-2x+1))-40+1=0



We calculate terms in parentheses: -(4x-2(-2x+1)), so:

4x-2(-2x+1)

We multiply parentheses

4x+4x-2

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

8x-(8x-2)-39=0

We get rid of parentheses

8x-8x+2-39=0

We add all the numbers together, and all the variables

-37!=0

There is no solution for this equation

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