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8(x-5)+4x=40+2x
We move all terms to the left:
8(x-5)+4x-(40+2x)=0
We add all the numbers together, and all the variables
8(x-5)+4x-(2x+40)=0
We add all the numbers together, and all the variables
4x+8(x-5)-(2x+40)=0
We multiply parentheses
4x+8x-(2x+40)-40=0
We get rid of parentheses
4x+8x-2x-40-40=0
We add all the numbers together, and all the variables
10x-80=0
We move all terms containing x to the left, all other terms to the right
10x=80
x=80/10
x=8
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