8(x-5)=-3(x-2)

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Solution for 8(x-5)=-3(x-2) equation: 



8(x-5)=-3(x-2)

We move all terms to the left:

8(x-5)-(-3(x-2))=0

We multiply parentheses

8x-(-3(x-2))-40=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

8x+3x-6-40=0

We add all the numbers together, and all the variables

11x-46=0

We move all terms containing x to the left, all other terms to the right

11x=46

x=46/11

x=4+2/11

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