8(x-5)=12(4x-1)

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Solution for 8(x-5)=12(4x-1) equation: 



8(x-5)=12(4x-1)

We move all terms to the left:

8(x-5)-(12(4x-1))=0

We multiply parentheses

8x-(12(4x-1))-40=0



We calculate terms in parentheses: -(12(4x-1)), so:

12(4x-1)

We multiply parentheses

48x-12

Back to the equation:

-(48x-12)



We get rid of parentheses

8x-48x+12-40=0

We add all the numbers together, and all the variables

-40x-28=0

We move all terms containing x to the left, all other terms to the right

-40x=28

x=28/-40

x=-7/10

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