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8(x-5)=2x+30-2(x+15)
We move all terms to the left:
8(x-5)-(2x+30-2(x+15))=0
We multiply parentheses
8x-(2x+30-2(x+15))-40=0
We calculate terms in parentheses: -(2x+30-2(x+15)), so:We add all the numbers together, and all the variables
2x+30-2(x+15)
determiningTheFunctionDomain 2x-2(x+15)+30
We multiply parentheses
2x-2x-30+30
We add all the numbers together, and all the variables
Back to the equation:
-()
8x=0
x=0/8
x=0
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