8(x-5)=3(2x-6)-(x+1)

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Solution for 8(x-5)=3(2x-6)-(x+1) equation: 



8(x-5)=3(2x-6)-(x+1)

We move all terms to the left:

8(x-5)-(3(2x-6)-(x+1))=0

We multiply parentheses

8x-(3(2x-6)-(x+1))-40=0



We calculate terms in parentheses: -(3(2x-6)-(x+1)), so:

3(2x-6)-(x+1)

We multiply parentheses

6x-(x+1)-18

We get rid of parentheses

6x-x-1-18

We add all the numbers together, and all the variables

5x-19

Back to the equation:

-(5x-19)



We get rid of parentheses

8x-5x+19-40=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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