8(x-5)=4(2x+3)+28

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Solution for 8(x-5)=4(2x+3)+28 equation:



8(x-5)=4(2x+3)+28
We move all terms to the left:
8(x-5)-(4(2x+3)+28)=0
We multiply parentheses
8x-(4(2x+3)+28)-40=0
We calculate terms in parentheses: -(4(2x+3)+28), so:
4(2x+3)+28
We multiply parentheses
8x+12+28
We add all the numbers together, and all the variables
8x+40
Back to the equation:
-(8x+40)
We get rid of parentheses
8x-8x-40-40=0
We add all the numbers together, and all the variables
-80!=0
There is no solution for this equation

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