8(x-6)+58=-3(2x-8)+14x

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Solution for 8(x-6)+58=-3(2x-8)+14x equation: 



8(x-6)+58=-3(2x-8)+14x

We move all terms to the left:

8(x-6)+58-(-3(2x-8)+14x)=0

We multiply parentheses

8x-(-3(2x-8)+14x)-48+58=0



We calculate terms in parentheses: -(-3(2x-8)+14x), so:

-3(2x-8)+14x

We add all the numbers together, and all the variables

14x-3(2x-8)

We multiply parentheses

14x-6x+24

We add all the numbers together, and all the variables

8x+24

Back to the equation:

-(8x+24)



We add all the numbers together, and all the variables

8x-(8x+24)+10=0

We get rid of parentheses

8x-8x-24+10=0

We add all the numbers together, and all the variables

-14!=0

There is no solution for this equation

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