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8(x-6)x=7
We move all terms to the left:
8(x-6)x-(7)=0
We multiply parentheses
8x^2-48x-7=0
a = 8; b = -48; c = -7;
Δ = b2-4ac
Δ = -482-4·8·(-7)
Δ = 2528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2528}=\sqrt{16*158}=\sqrt{16}*\sqrt{158}=4\sqrt{158}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-4\sqrt{158}}{2*8}=\frac{48-4\sqrt{158}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+4\sqrt{158}}{2*8}=\frac{48+4\sqrt{158}}{16} $
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