8(y+1)=10(y-2)

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Solution for 8(y+1)=10(y-2) equation:


Simplifying
8(y + 1) = 10(y + -2)

Reorder the terms:
8(1 + y) = 10(y + -2)
(1 * 8 + y * 8) = 10(y + -2)
(8 + 8y) = 10(y + -2)

Reorder the terms:
8 + 8y = 10(-2 + y)
8 + 8y = (-2 * 10 + y * 10)
8 + 8y = (-20 + 10y)

Solving
8 + 8y = -20 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
8 + 8y + -10y = -20 + 10y + -10y

Combine like terms: 8y + -10y = -2y
8 + -2y = -20 + 10y + -10y

Combine like terms: 10y + -10y = 0
8 + -2y = -20 + 0
8 + -2y = -20

Add '-8' to each side of the equation.
8 + -8 + -2y = -20 + -8

Combine like terms: 8 + -8 = 0
0 + -2y = -20 + -8
-2y = -20 + -8

Combine like terms: -20 + -8 = -28
-2y = -28

Divide each side by '-2'.
y = 14

Simplifying
y = 14

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