8(y+1)=20(3y+1)

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Solution for 8(y+1)=20(3y+1) equation:



8(y+1)=20(3y+1)
We move all terms to the left:
8(y+1)-(20(3y+1))=0
We multiply parentheses
8y-(20(3y+1))+8=0
We calculate terms in parentheses: -(20(3y+1)), so:
20(3y+1)
We multiply parentheses
60y+20
Back to the equation:
-(60y+20)
We get rid of parentheses
8y-60y-20+8=0
We add all the numbers together, and all the variables
-52y-12=0
We move all terms containing y to the left, all other terms to the right
-52y=12
y=12/-52
y=-3/13

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