8(y+1)=20(3y+1)

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Solution for 8(y+1)=20(3y+1) equation: 



8(y+1)=20(3y+1)

We move all terms to the left:

8(y+1)-(20(3y+1))=0

We multiply parentheses

8y-(20(3y+1))+8=0



We calculate terms in parentheses: -(20(3y+1)), so:

20(3y+1)

We multiply parentheses

60y+20

Back to the equation:

-(60y+20)



We get rid of parentheses

8y-60y-20+8=0

We add all the numbers together, and all the variables

-52y-12=0

We move all terms containing y to the left, all other terms to the right

-52y=12

y=12/-52

y=-3/13

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