8(y+1)=2y-12

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Solution for 8(y+1)=2y-12 equation: 



8(y+1)=2y-12

We move all terms to the left:

8(y+1)-(2y-12)=0

We multiply parentheses

8y-(2y-12)+8=0

We get rid of parentheses

8y-2y+12+8=0

We add all the numbers together, and all the variables

6y+20=0

We move all terms containing y to the left, all other terms to the right

6y=-20

y=-20/6

y=-3+1/3

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