8(y+10)+y=4(y+4)-4

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Solution for 8(y+10)+y=4(y+4)-4 equation: 



8(y+10)+y=4(y+4)-4

We move all terms to the left:

8(y+10)+y-(4(y+4)-4)=0

We add all the numbers together, and all the variables

y+8(y+10)-(4(y+4)-4)=0

We multiply parentheses

y+8y-(4(y+4)-4)+80=0



We calculate terms in parentheses: -(4(y+4)-4), so:

4(y+4)-4

We multiply parentheses

4y+16-4

We add all the numbers together, and all the variables

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

9y-(4y+12)+80=0

We get rid of parentheses

9y-4y-12+80=0

We add all the numbers together, and all the variables

5y+68=0

We move all terms containing y to the left, all other terms to the right

5y=-68

y=-68/5

y=-13+3/5

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