8(y+2)+2y=5(y+6)+1

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Solution for 8(y+2)+2y=5(y+6)+1 equation: 



8(y+2)+2y=5(y+6)+1

We move all terms to the left:

8(y+2)+2y-(5(y+6)+1)=0

We add all the numbers together, and all the variables

2y+8(y+2)-(5(y+6)+1)=0

We multiply parentheses

2y+8y-(5(y+6)+1)+16=0



We calculate terms in parentheses: -(5(y+6)+1), so:

5(y+6)+1

We multiply parentheses

5y+30+1

We add all the numbers together, and all the variables

5y+31

Back to the equation:

-(5y+31)



We add all the numbers together, and all the variables

10y-(5y+31)+16=0

We get rid of parentheses

10y-5y-31+16=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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