8(y+2)+3=6y-8

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Solution for 8(y+2)+3=6y-8 equation: 



8(y+2)+3=6y-8

We move all terms to the left:

8(y+2)+3-(6y-8)=0

We multiply parentheses

8y-(6y-8)+16+3=0

We get rid of parentheses

8y-6y+8+16+3=0

We add all the numbers together, and all the variables

2y+27=0

We move all terms containing y to the left, all other terms to the right

2y=-27

y=-27/2

y=-13+1/2

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