8(y+2)+5(y-3)=27

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Solution for 8(y+2)+5(y-3)=27 equation: 



8(y+2)+5(y-3)=27

We move all terms to the left:

8(y+2)+5(y-3)-(27)=0

We multiply parentheses

8y+5y+16-15-27=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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