8(y+2)-7(y+1)=5

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Solution for 8(y+2)-7(y+1)=5 equation:


Simplifying
8(y + 2) + -7(y + 1) = 5

Reorder the terms:
8(2 + y) + -7(y + 1) = 5
(2 * 8 + y * 8) + -7(y + 1) = 5
(16 + 8y) + -7(y + 1) = 5

Reorder the terms:
16 + 8y + -7(1 + y) = 5
16 + 8y + (1 * -7 + y * -7) = 5
16 + 8y + (-7 + -7y) = 5

Reorder the terms:
16 + -7 + 8y + -7y = 5

Combine like terms: 16 + -7 = 9
9 + 8y + -7y = 5

Combine like terms: 8y + -7y = 1y
9 + 1y = 5

Solving
9 + 1y = 5

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 1y = 5 + -9

Combine like terms: 9 + -9 = 0
0 + 1y = 5 + -9
1y = 5 + -9

Combine like terms: 5 + -9 = -4
1y = -4

Divide each side by '1'.
y = -4

Simplifying
y = -4

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