8(y+2)-7(y+1)=6

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Solution for 8(y+2)-7(y+1)=6 equation:


Simplifying
8(y + 2) + -7(y + 1) = 6

Reorder the terms:
8(2 + y) + -7(y + 1) = 6
(2 * 8 + y * 8) + -7(y + 1) = 6
(16 + 8y) + -7(y + 1) = 6

Reorder the terms:
16 + 8y + -7(1 + y) = 6
16 + 8y + (1 * -7 + y * -7) = 6
16 + 8y + (-7 + -7y) = 6

Reorder the terms:
16 + -7 + 8y + -7y = 6

Combine like terms: 16 + -7 = 9
9 + 8y + -7y = 6

Combine like terms: 8y + -7y = 1y
9 + 1y = 6

Solving
9 + 1y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 1y = 6 + -9

Combine like terms: 9 + -9 = 0
0 + 1y = 6 + -9
1y = 6 + -9

Combine like terms: 6 + -9 = -3
1y = -3

Divide each side by '1'.
y = -3

Simplifying
y = -3

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