8(y+2)=2(3y-4)

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Solution for 8(y+2)=2(3y-4) equation: 



8(y+2)=2(3y-4)

We move all terms to the left:

8(y+2)-(2(3y-4))=0

We multiply parentheses

8y-(2(3y-4))+16=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We get rid of parentheses

8y-6y+8+16=0

We add all the numbers together, and all the variables

2y+24=0

We move all terms containing y to the left, all other terms to the right

2y=-24

y=-24/2

y=-12

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