8(y+2)=4(2y+3)+4

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Solution for 8(y+2)=4(2y+3)+4 equation: 


Simplifying
8(y + 2) = 4(2y + 3) + 4

Reorder the terms:
8(2 + y) = 4(2y + 3) + 4
(2 * 8 + y * 8) = 4(2y + 3) + 4
(16 + 8y) = 4(2y + 3) + 4

Reorder the terms:
16 + 8y = 4(3 + 2y) + 4
16 + 8y = (3 * 4 + 2y * 4) + 4
16 + 8y = (12 + 8y) + 4

Reorder the terms:
16 + 8y = 12 + 4 + 8y

Combine like terms: 12 + 4 = 16
16 + 8y = 16 + 8y

Add '-16' to each side of the equation.
16 + -16 + 8y = 16 + -16 + 8y

Combine like terms: 16 + -16 = 0
0 + 8y = 16 + -16 + 8y
8y = 16 + -16 + 8y

Combine like terms: 16 + -16 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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