8(y+2)=5(2y-4)

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Solution for 8(y+2)=5(2y-4) equation: 



8(y+2)=5(2y-4)

We move all terms to the left:

8(y+2)-(5(2y-4))=0

We multiply parentheses

8y-(5(2y-4))+16=0



We calculate terms in parentheses: -(5(2y-4)), so:

5(2y-4)

We multiply parentheses

10y-20

Back to the equation:

-(10y-20)



We get rid of parentheses

8y-10y+20+16=0

We add all the numbers together, and all the variables

-2y+36=0

We move all terms containing y to the left, all other terms to the right

-2y=-36

y=-36/-2

y=+18

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