8(y+3)+y=3(y+2)-5

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Solution for 8(y+3)+y=3(y+2)-5 equation: 



8(y+3)+y=3(y+2)-5

We move all terms to the left:

8(y+3)+y-(3(y+2)-5)=0

We add all the numbers together, and all the variables

y+8(y+3)-(3(y+2)-5)=0

We multiply parentheses

y+8y-(3(y+2)-5)+24=0



We calculate terms in parentheses: -(3(y+2)-5), so:

3(y+2)-5

We multiply parentheses

3y+6-5

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We add all the numbers together, and all the variables

9y-(3y+1)+24=0

We get rid of parentheses

9y-3y-1+24=0

We add all the numbers together, and all the variables

6y+23=0

We move all terms containing y to the left, all other terms to the right

6y=-23

y=-23/6

y=-3+5/6

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