8(y+3)-5(4y+7)=3(y-1)-4(y-1)

Solution for 8(y+3)-5(4y+7)=3(y-1)-4(y-1) equation:

8(y+3)-5(4y+7)=3(y-1)-4(y-1)

We move all terms to the left:

8(y+3)-5(4y+7)-(3(y-1)-4(y-1))=0

We multiply parentheses

8y-20y-(3(y-1)-4(y-1))+24-35=0


We calculate terms in parentheses: -(3(y-1)-4(y-1)), so:

3(y-1)-4(y-1)

We multiply parentheses

3y-4y-3+4

We add all the numbers together, and all the variables

-1y+1

Back to the equation:

-(-1y+1)


We add all the numbers together, and all the variables

-12y-(-1y+1)-11=0

We get rid of parentheses

-12y+1y-1-11=0

We add all the numbers together, and all the variables

-11y-12=0

We move all terms containing y to the left, all other terms to the right

-11y=12

y=12/-11

y=-1+1/11