8(y+3)=6(y+4)+2y

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Solution for 8(y+3)=6(y+4)+2y equation: 



8(y+3)=6(y+4)+2y

We move all terms to the left:

8(y+3)-(6(y+4)+2y)=0

We multiply parentheses

8y-(6(y+4)+2y)+24=0



We calculate terms in parentheses: -(6(y+4)+2y), so:

6(y+4)+2y

We add all the numbers together, and all the variables

2y+6(y+4)

We multiply parentheses

2y+6y+24

We add all the numbers together, and all the variables

8y+24

Back to the equation:

-(8y+24)



We get rid of parentheses

8y-8y-24+24=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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