8(y+4)-12=6y

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Solution for 8(y+4)-12=6y equation: 



8(y+4)-12=6y

We move all terms to the left:

8(y+4)-12-(6y)=0

We add all the numbers together, and all the variables

-6y+8(y+4)-12=0

We multiply parentheses

-6y+8y+32-12=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10

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