8(y+4)-2(y-1)=10-3(y-20)

Solution for 8(y+4)-2(y-1)=10-3(y-20) equation:

8(y+4)-2(y-1)=10-3(y-20)

We move all terms to the left:

8(y+4)-2(y-1)-(10-3(y-20))=0

We multiply parentheses

8y-2y-(10-3(y-20))+32+2=0


We calculate terms in parentheses: -(10-3(y-20)), so:

10-3(y-20)

determiningTheFunctionDomain
-3(y-20)+10

We multiply parentheses

-3y+60+10

We add all the numbers together, and all the variables

-3y+70

Back to the equation:

-(-3y+70)


We add all the numbers together, and all the variables

6y-(-3y+70)+34=0

We get rid of parentheses

6y+3y-70+34=0

We add all the numbers together, and all the variables

9y-36=0

We move all terms containing y to the left, all other terms to the right

9y=36

y=36/9

y=4