8(y+4)-2(y-1)=7-3y

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Solution for 8(y+4)-2(y-1)=7-3y equation: 



8(y+4)-2(y-1)=7-3y

We move all terms to the left:

8(y+4)-2(y-1)-(7-3y)=0

We add all the numbers together, and all the variables

8(y+4)-2(y-1)-(-3y+7)=0

We multiply parentheses

8y-2y-(-3y+7)+32+2=0

We get rid of parentheses

8y-2y+3y-7+32+2=0

We add all the numbers together, and all the variables

9y+27=0

We move all terms containing y to the left, all other terms to the right

9y=-27

y=-27/9

y=-3

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