8(y+4)-4(y-3)=6(y+5)

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Solution for 8(y+4)-4(y-3)=6(y+5) equation: 



8(y+4)-4(y-3)=6(y+5)

We move all terms to the left:

8(y+4)-4(y-3)-(6(y+5))=0

We multiply parentheses

8y-4y-(6(y+5))+32+12=0



We calculate terms in parentheses: -(6(y+5)), so:

6(y+5)

We multiply parentheses

6y+30

Back to the equation:

-(6y+30)



We add all the numbers together, and all the variables

4y-(6y+30)+44=0

We get rid of parentheses

4y-6y-30+44=0

We add all the numbers together, and all the variables

-2y+14=0

We move all terms containing y to the left, all other terms to the right

-2y=-14

y=-14/-2

y=+7

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