8(y+4)=(7y+38)

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Solution for 8(y+4)=(7y+38) equation: 



8(y+4)=(7y+38)

We move all terms to the left:

8(y+4)-((7y+38))=0

We multiply parentheses

8y-((7y+38))+32=0



We calculate terms in parentheses: -((7y+38)), so:

(7y+38)

We get rid of parentheses

7y+38

Back to the equation:

-(7y+38)



We get rid of parentheses

8y-7y-38+32=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6

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