8(y+4)=-8y-32

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Solution for 8(y+4)=-8y-32 equation: 



8(y+4)=-8y-32

We move all terms to the left:

8(y+4)-(-8y-32)=0

We multiply parentheses

8y-(-8y-32)+32=0

We get rid of parentheses

8y+8y+32+32=0

We add all the numbers together, and all the variables

16y+64=0

We move all terms containing y to the left, all other terms to the right

16y=-64

y=-64/16

y=-4

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