8(y+4)=6(y+2)

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Solution for 8(y+4)=6(y+2) equation: 



8(y+4)=6(y+2)

We move all terms to the left:

8(y+4)-(6(y+2))=0

We multiply parentheses

8y-(6(y+2))+32=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

8y-6y-12+32=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10

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