8(y+6)+y=4(y+2)-8

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Solution for 8(y+6)+y=4(y+2)-8 equation:



8(y+6)+y=4(y+2)-8
We move all terms to the left:
8(y+6)+y-(4(y+2)-8)=0
We add all the numbers together, and all the variables
y+8(y+6)-(4(y+2)-8)=0
We multiply parentheses
y+8y-(4(y+2)-8)+48=0
We calculate terms in parentheses: -(4(y+2)-8), so:
4(y+2)-8
We multiply parentheses
4y+8-8
We add all the numbers together, and all the variables
4y
Back to the equation:
-(4y)
We add all the numbers together, and all the variables
5y+48=0
We move all terms containing y to the left, all other terms to the right
5y=-48
y=-48/5
y=-9+3/5

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