8(y+6)+y=4(y+2)-8

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Solution for 8(y+6)+y=4(y+2)-8 equation: 



8(y+6)+y=4(y+2)-8

We move all terms to the left:

8(y+6)+y-(4(y+2)-8)=0

We add all the numbers together, and all the variables

y+8(y+6)-(4(y+2)-8)=0

We multiply parentheses

y+8y-(4(y+2)-8)+48=0



We calculate terms in parentheses: -(4(y+2)-8), so:

4(y+2)-8

We multiply parentheses

4y+8-8

We add all the numbers together, and all the variables

4y

Back to the equation:

-(4y)



We add all the numbers together, and all the variables

5y+48=0

We move all terms containing y to the left, all other terms to the right

5y=-48

y=-48/5

y=-9+3/5

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