8(y+6)-3(y-4)=2(y-5)

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Solution for 8(y+6)-3(y-4)=2(y-5) equation: 



8(y+6)-3(y-4)=2(y-5)

We move all terms to the left:

8(y+6)-3(y-4)-(2(y-5))=0

We multiply parentheses

8y-3y-(2(y-5))+48+12=0



We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We add all the numbers together, and all the variables

5y-(2y-10)+60=0

We get rid of parentheses

5y-2y+10+60=0

We add all the numbers together, and all the variables

3y+70=0

We move all terms containing y to the left, all other terms to the right

3y=-70

y=-70/3

y=-23+1/3

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