8(y+7)-2(y-5)=3(y-3)

Solution for 8(y+7)-2(y-5)=3(y-3) equation:

8(y+7)-2(y-5)=3(y-3)

We move all terms to the left:

8(y+7)-2(y-5)-(3(y-3))=0

We multiply parentheses

8y-2y-(3(y-3))+56+10=0


We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)


We add all the numbers together, and all the variables

6y-(3y-9)+66=0

We get rid of parentheses

6y-3y+9+66=0

We add all the numbers together, and all the variables

3y+75=0

We move all terms containing y to the left, all other terms to the right

3y=-75

y=-75/3

y=-25