8(y+7)-3(y-4)=2(y-5)

Solution for 8(y+7)-3(y-4)=2(y-5) equation:

8(y+7)-3(y-4)=2(y-5)

We move all terms to the left:

8(y+7)-3(y-4)-(2(y-5))=0

We multiply parentheses

8y-3y-(2(y-5))+56+12=0


We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)


We add all the numbers together, and all the variables

5y-(2y-10)+68=0

We get rid of parentheses

5y-2y+10+68=0

We add all the numbers together, and all the variables

3y+78=0

We move all terms containing y to the left, all other terms to the right

3y=-78

y=-78/3

y=-26