8(y+7)-4(y-4)=2(y-3)

Solution for 8(y+7)-4(y-4)=2(y-3) equation:

8(y+7)-4(y-4)=2(y-3)

We move all terms to the left:

8(y+7)-4(y-4)-(2(y-3))=0

We multiply parentheses

8y-4y-(2(y-3))+56+16=0


We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)


We add all the numbers together, and all the variables

4y-(2y-6)+72=0

We get rid of parentheses

4y-2y+6+72=0

We add all the numbers together, and all the variables

2y+78=0

We move all terms containing y to the left, all other terms to the right

2y=-78

y=-78/2

y=-39