8(y+8)-3(y-5)=2(y-4)

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Solution for 8(y+8)-3(y-5)=2(y-4) equation: 



8(y+8)-3(y-5)=2(y-4)

We move all terms to the left:

8(y+8)-3(y-5)-(2(y-4))=0

We multiply parentheses

8y-3y-(2(y-4))+64+15=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

5y-(2y-8)+79=0

We get rid of parentheses

5y-2y+8+79=0

We add all the numbers together, and all the variables

3y+87=0

We move all terms containing y to the left, all other terms to the right

3y=-87

y=-87/3

y=-29

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