8(y-1)-3y=6(2y-5)

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Solution for 8(y-1)-3y=6(2y-5) equation: 



8(y-1)-3y=6(2y-5)

We move all terms to the left:

8(y-1)-3y-(6(2y-5))=0

We add all the numbers together, and all the variables

-3y+8(y-1)-(6(2y-5))=0

We multiply parentheses

-3y+8y-(6(2y-5))-8=0



We calculate terms in parentheses: -(6(2y-5)), so:

6(2y-5)

We multiply parentheses

12y-30

Back to the equation:

-(12y-30)



We add all the numbers together, and all the variables

5y-(12y-30)-8=0

We get rid of parentheses

5y-12y+30-8=0

We add all the numbers together, and all the variables

-7y+22=0

We move all terms containing y to the left, all other terms to the right

-7y=-22

y=-22/-7

y=3+1/7

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