8(y-1)=-3y-41

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Solution for 8(y-1)=-3y-41 equation: 



8(y-1)=-3y-41

We move all terms to the left:

8(y-1)-(-3y-41)=0

We multiply parentheses

8y-(-3y-41)-8=0

We get rid of parentheses

8y+3y+41-8=0

We add all the numbers together, and all the variables

11y+33=0

We move all terms containing y to the left, all other terms to the right

11y=-33

y=-33/11

y=-3

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