8(y-1)=4(y+3)

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Solution for 8(y-1)=4(y+3) equation: 



8(y-1)=4(y+3)

We move all terms to the left:

8(y-1)-(4(y+3))=0

We multiply parentheses

8y-(4(y+3))-8=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

8y-4y-12-8=0

We add all the numbers together, and all the variables

4y-20=0

We move all terms containing y to the left, all other terms to the right

4y=20

y=20/4

y=5

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