8(y-2)-7y=6(y+3)-6(y-1

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Solution for 8(y-2)-7y=6(y+3)-6(y-1 equation: 



8(y-2)-7y=6(y+3)-6(y-1

We move all terms to the left:

8(y-2)-7y-(6(y+3)-6(y-1)=0

We add all the numbers together, and all the variables

-7y+8(y-2)-(6(y+3)-6(y-1)=0

We multiply parentheses

-7y+8y-(6(y+3)-6(y-1)-16=0

We add all the numbers together, and all the variables

y-(6(y+3)-6(y-1)-16=0

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