8(y-2)-y+12=10

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Solution for 8(y-2)-y+12=10 equation: 



8(y-2)-y+12=10

We move all terms to the left:

8(y-2)-y+12-(10)=0

We add all the numbers together, and all the variables

-1y+8(y-2)+2=0

We multiply parentheses

-1y+8y-16+2=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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