8(y-2)=6(2y-1)-2y

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Solution for 8(y-2)=6(2y-1)-2y equation: 



8(y-2)=6(2y-1)-2y

We move all terms to the left:

8(y-2)-(6(2y-1)-2y)=0

We multiply parentheses

8y-(6(2y-1)-2y)-16=0



We calculate terms in parentheses: -(6(2y-1)-2y), so:

6(2y-1)-2y

We add all the numbers together, and all the variables

-2y+6(2y-1)

We multiply parentheses

-2y+12y-6

We add all the numbers together, and all the variables

10y-6

Back to the equation:

-(10y-6)



We get rid of parentheses

8y-10y+6-16=0

We add all the numbers together, and all the variables

-2y-10=0

We move all terms containing y to the left, all other terms to the right

-2y=10

y=10/-2

y=-5

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