8(y-3)+4(y+1)=28

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Solution for 8(y-3)+4(y+1)=28 equation:


Simplifying
8(y + -3) + 4(y + 1) = 28

Reorder the terms:
8(-3 + y) + 4(y + 1) = 28
(-3 * 8 + y * 8) + 4(y + 1) = 28
(-24 + 8y) + 4(y + 1) = 28

Reorder the terms:
-24 + 8y + 4(1 + y) = 28
-24 + 8y + (1 * 4 + y * 4) = 28
-24 + 8y + (4 + 4y) = 28

Reorder the terms:
-24 + 4 + 8y + 4y = 28

Combine like terms: -24 + 4 = -20
-20 + 8y + 4y = 28

Combine like terms: 8y + 4y = 12y
-20 + 12y = 28

Solving
-20 + 12y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 12y = 28 + 20

Combine like terms: -20 + 20 = 0
0 + 12y = 28 + 20
12y = 28 + 20

Combine like terms: 28 + 20 = 48
12y = 48

Divide each side by '12'.
y = 4

Simplifying
y = 4

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